Summary

You searched for: sol=1936

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1

New Number: 5.63 |  AESZ: 271  |  Superseeker: 10912 71557619232  |  Hash: c20fda7ad02ecc06f9b3f74bf4327d05  

Degree: 5

\(\theta^4+2^{4} x\left(2304\theta^4-3072\theta^3-2224\theta^2-688\theta-121\right)+2^{17} x^{2}\left(1792\theta^4-8192\theta^3+920\theta^2+344\theta+235\right)-2^{28} x^{3}\left(8704\theta^4+6144\theta^3+9872\theta^2+4368\theta+1201\right)-2^{44} 5 x^{4}\left(48\theta^4-37\theta^2-37\theta-13\right)+2^{60} 5^{2} x^{5}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 1936, 5433616, 17299986688, 58672579116304, ...
--> OEIS
Normalized instanton numbers (n0=1): 10912, -20731504, 71557619232, -326717237089712, 1743820693922321120, ... ; Common denominator:...

Discriminant

\((1+4096z)(20480z+1)^2(4096z-1)^2\)

Local exponents

\(-\frac{ 1}{ 4096}\)\(-\frac{ 1}{ 20480}\)\(0\)\(\frac{ 1}{ 4096}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(0\)\(-\frac{ 1}{ 4}\)\(1\)
\(1\)\(3\)\(0\)\(1\)\(1\)
\(2\)\(4\)\(0\)\(\frac{ 5}{ 4}\)\(1\)

Note:

There is a second MUM-point at infinity,
corresponding to Operator AESZ 270 /5.62

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2

New Number: 13.15 |  AESZ:  |  Superseeker: 6 626/3  |  Hash: 3e24fdfe8119ac950ce846460f109e44  

Degree: 13

\(\theta^4-2 x\left(16\theta^4+50\theta^3+39\theta^2+14\theta+2\right)-2^{2} x^{2}\left(219\theta^4+390\theta^3+335\theta^2+214\theta+62\right)-2^{4} x^{3}\left(115\theta^4+1068\theta^3+2660\theta^2+2022\theta+582\right)+2^{6} x^{4}\left(122\theta^4-788\theta^3+151\theta^2-913\theta-696\right)-2^{8} 3 x^{5}\left(303\theta^4-1488\theta^3-2955\theta^2-2550\theta-827\right)-2^{10} 3 x^{6}\left(37\theta^4+714\theta^3-5760\theta^2-8319\theta-3550\right)-2^{13} 3 x^{7}\left(101\theta^4+82\theta^3+102\theta^2-1679\theta-1322\right)+2^{15} 3 x^{8}\left(48\theta^4+948\theta^3-461\theta^2-1447\theta-628\right)-2^{17} x^{9}\left(89\theta^4-4392\theta^3-6123\theta^2-450\theta+1902\right)-2^{20} x^{10}\left(121\theta^4-532\theta^3-3072\theta^2-3697\theta-1348\right)+2^{23} 5 x^{11}(\theta+1)(21\theta^3+63\theta^2+206\theta+218)+2^{25} 5^{2} x^{12}(\theta+2)(\theta+1)(2\theta^2-12\theta-27)+2^{27} 5^{3} x^{13}(\theta+1)(\theta+2)^2(\theta+3)\)

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Coefficients of the holomorphic solution: 1, 4, 76, 1936, 57820, ...
--> OEIS
Normalized instanton numbers (n0=1): 6, 41/4, 626/3, 12349/8, 33062, ... ; Common denominator:...

Discriminant

\((4z-1)(4z+1)(16z^2+4z+1)(640z^3+96z^2+48z-1)(1+6z-48z^2+320z^3)^2\)

Local exponents

\(-\frac{ 1}{ 4}\)\(-\frac{ 1}{ 8}-\frac{ 1}{ 8}\sqrt{ 3}I\)\(-\frac{ 1}{ 8}+\frac{ 1}{ 8}\sqrt{ 3}I\) ≈\(-0.084967-0.266773I\) ≈\(-0.084967+0.266773I\) ≈\(-0.082432\)\(0\) ≈\(0.019933\) ≈\(0.116216-0.156217I\) ≈\(0.116216+0.156217I\)\(\frac{ 1}{ 4}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(1\)\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)\(2\)
\(1\)\(1\)\(1\)\(1\)\(1\)\(3\)\(0\)\(1\)\(3\)\(3\)\(1\)\(2\)
\(2\)\(2\)\(2\)\(2\)\(2\)\(4\)\(0\)\(2\)\(4\)\(4\)\(2\)\(3\)

Note:

This is operator "13.15" from ...

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