Summary

You searched for: sol=168840

Your search produced exactly one match

1

New Number: 6.18 |  AESZ:  |  Superseeker: 3 64  |  Hash: b127e33287ed87a366c178fc4678cdc4  

Degree: 6

\(\theta^4-x\left(18+94\theta+199\theta^2+210\theta^3+105\theta^4\right)+2 x^{2}\left(2095\theta^4+8380\theta^3+13298\theta^2+9836\theta+2850\right)-2^{2} 3^{2} x^{3}\left(2310\theta^4+13860\theta^3+30739\theta^2+29847\theta+10763\right)+2^{3} 3^{3} x^{4}\left(4044\theta^4+32352\theta^3+91997\theta^2+109172\theta+45693\right)-2^{4} 3^{3} 5^{2} 7 x^{5}(\theta+4)(\theta+1)(61\theta^2+305\theta+345)+2^{5} 3^{5} 5^{2} 7^{2} x^{6}(\theta+5)(\theta+4)(\theta+2)(\theta+1)\)

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Coefficients of the holomorphic solution: 1, 18, 348, 7320, 168840, ...
--> OEIS
Normalized instanton numbers (n0=1): 3, -4, 64, -253, 4292, ... ; Common denominator:...

Discriminant

\((6z-1)(15z-1)(14z-1)(42z-1)(18z-1)(10z-1)\)

Local exponents

\(0\)\(\frac{ 1}{ 42}\)\(\frac{ 1}{ 18}\)\(\frac{ 1}{ 15}\)\(\frac{ 1}{ 14}\)\(\frac{ 1}{ 10}\)\(\frac{ 1}{ 6}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)\(1\)\(2\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)\(1\)\(4\)
\(0\)\(2\)\(2\)\(2\)\(2\)\(2\)\(2\)\(5\)

Note:

This is operator "6.18" from ...

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