Summary

You searched for: sol=16524

Your search produced exactly one match

1

New Number: 7.16 |  AESZ:  |  Superseeker: 22/5 68  |  Hash: 660211ce6175f36772066594bfc33cbb  

Degree: 7

\(5^{2} \theta^4-2 5 x\theta(15+71\theta+112\theta^2+38\theta^3)-2^{2} x^{2}\left(4364\theta^4+15872\theta^3+24679\theta^2+19360\theta+6000\right)-2^{4} 3^{2} 5 x^{3}\left(92\theta^4+224\theta^3+103\theta^2-176\theta-165\right)+2^{6} 3^{2} x^{4}\left(1228\theta^4+10496\theta^3+30154\theta^2+35736\theta+14715\right)+2^{9} 3^{4} x^{5}(\theta+1)(38\theta^3+74\theta^2-304\theta-495)-2^{10} 3^{4} x^{6}(2\theta+13)(2\theta+3)(17\theta+39)(\theta+1)-2^{12} 3^{6} x^{7}(\theta+1)(2\theta+5)(2\theta+3)(\theta+3)\)

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Coefficients of the holomorphic solution: 1, 0, 60, 480, 16524, ...
--> OEIS
Normalized instanton numbers (n0=1): 22/5, 8, 68, 3292/5, 38826/5, ... ; Common denominator:...

Discriminant

\(-(-1+36z)(12z+5)^2(12z+1)^2(4z-1)^2\)

Local exponents

\(-\frac{ 5}{ 12}\)\(-\frac{ 1}{ 12}\)\(0\)\(\frac{ 1}{ 36}\)\(\frac{ 1}{ 4}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(0\)\(0\)\(1\)\(\frac{ 1}{ 2}\)\(\frac{ 3}{ 2}\)
\(3\)\(1\)\(0\)\(1\)\(\frac{ 1}{ 2}\)\(\frac{ 5}{ 2}\)
\(4\)\(1\)\(0\)\(2\)\(1\)\(3\)

Note:

This is operator "7.16" from ...

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