Summary

You searched for: sol=138259216

Your search produced exactly one match

1

New Number: 8.56 |  AESZ:  |  Superseeker: 80 266256  |  Hash: b561c9f1501dce5c055c95391a2176d3  

Degree: 8

\(\theta^4-2^{4} x\left(34\theta^4+44\theta^3+31\theta^2+9\theta+1\right)+2^{9} x^{2}\left(94\theta^4-14\theta^3-168\theta^2-98\theta-19\right)-2^{12} x^{3}\left(368\theta^4-1104\theta^3-1505\theta^2-549\theta-60\right)+2^{16} x^{4}\left(28\theta^4-2740\theta^3-154\theta^2+928\theta+331\right)+2^{20} x^{5}\left(678\theta^4+1116\theta^3-2997\theta^2-2295\theta-505\right)-2^{26} x^{6}\left(94\theta^4-561\theta^3-508\theta^2-132\theta+6\right)-2^{28} 5 x^{7}\left(92\theta^4+160\theta^3+97\theta^2+17\theta-2\right)-2^{32} 5^{2} x^{8}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 16, 2512, 533248, 138259216, ...
--> OEIS
Normalized instanton numbers (n0=1): 80, 3554, 266256, 31532007, 4663446128, ... ; Common denominator:...

Discriminant

\(-(16z+1)(4096z^3+4864z^2+432z-1)(1-64z+1280z^2)^2\)

Local exponents

≈\(-1.090586\) ≈\(-0.099171\)\(-\frac{ 1}{ 16}\)\(0\) ≈\(0.002257\)\(\frac{ 1}{ 40}-\frac{ 1}{ 80}I\)\(\frac{ 1}{ 40}+\frac{ 1}{ 80}I\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(3\)\(3\)\(1\)
\(2\)\(2\)\(2\)\(0\)\(2\)\(4\)\(4\)\(1\)

Note:

This is operator "8.56" from ...

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