Summary

You searched for: sol=137548

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1

New Number: 9.5 |  AESZ:  |  Superseeker: 17/3 4127/9  |  Hash: 98a7e046a956f1c9ec13973072ab8283  

Degree: 9

\(3^{2} \theta^4-3 x\left(152\theta^4+316\theta^3+245\theta^2+87\theta+12\right)-x^{2}\left(5808+25608\theta+43193\theta^2+31076\theta^3+8807\theta^4\right)-2 x^{3}\left(10633\theta^4+106320\theta^3+235087\theta^2+185292\theta+52896\right)+2^{2} x^{4}\left(65651\theta^4+19144\theta^3-434467\theta^2-508704\theta-175376\right)+2^{3} x^{5}\left(151497\theta^4+645060\theta^3+272053\theta^2-269230\theta-183720\right)-2^{8} x^{6}\left(3386\theta^4-52470\theta^3-83275\theta^2-46299\theta-7926\right)-2^{10} x^{7}\left(11425\theta^4+14072\theta^3-3794\theta^2-13632\theta-5575\right)-2^{15} x^{8}(590\theta^2+1126\theta+597)(\theta+1)^2-2^{20} 3^{2} x^{9}(\theta+1)^2(\theta+2)^2\)

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Coefficients of the holomorphic solution: 1, 4, 108, 3496, 137548, ...
--> OEIS
Normalized instanton numbers (n0=1): 17/3, 257/6, 4127/9, 23827/3, 496999/3, ... ; Common denominator:...

Discriminant

\(-(9z+1)(2z+1)(z+1)(128z^2+64z-1)(-3-2z+64z^2)^2\)

Local exponents

\(-1\)\(-\frac{ 1}{ 4}-\frac{ 3}{ 16}\sqrt{ 2}\)\(-\frac{ 1}{ 2}\)\(\frac{ 1}{ 64}-\frac{ 1}{ 64}\sqrt{ 193}\)\(-\frac{ 1}{ 9}\)\(0\)\(-\frac{ 1}{ 4}+\frac{ 3}{ 16}\sqrt{ 2}\)\(\frac{ 1}{ 64}+\frac{ 1}{ 64}\sqrt{ 193}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(1\)\(1\)\(1\)\(3\)\(1\)\(0\)\(1\)\(3\)\(2\)
\(2\)\(2\)\(2\)\(4\)\(2\)\(0\)\(2\)\(4\)\(2\)

Note:

This is operator "9.5" from ...

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