Summary

You searched for: sol=13390/529

Your search produced exactly one match

1

New Number: 6.19 |  AESZ:  |  Superseeker: 2/23 27/23  |  Hash: 38a2cec750ea75c0fd64ef0a4286a801  

Degree: 6

\(23^{6} \theta^4+2 23^{5} x\left(224\theta^4+448\theta^3+449\theta^2+225\theta+45\right)+2^{2} 23^{4} x^{2}\left(6271\theta^4+25084\theta^3+40435\theta^2+30702\theta+9035\right)-23^{3} x^{3}\left(8650483\theta^4+51902898\theta^3+114278033\theta^2+109271058\theta+38421000\right)-2^{2} 5 23^{2} x^{4}\left(37482007\theta^4+299856056\theta^3+854051365\theta^2+1017357012\theta+426206376\right)-2^{4} 3 5^{2} 7 11 19 23 x^{5}(\theta+4)(\theta+1)(10889\theta^2+54445\theta+62408)-2^{6} 3^{2} 5^{3} 7^{2} 11^{2} 19^{2} x^{6}(\theta+5)(\theta+4)(\theta+2)(\theta+1)\)

Maple   LaTex

Coefficients of the holomorphic solution: 1, -90/23, 13390/529, -2157300/12167, 398261070/279841, ...
--> OEIS
Normalized instanton numbers (n0=1): 2/23, 18/23, 27/23, 136/23, 395/23, ... ; Common denominator:...

Discriminant

\(-(228z+23)(21z+23)(140z-23)(44z+23)(5225z^2+6785z+529)\)

Local exponents

\(-\frac{ 1357}{ 2090}-\frac{ 529}{ 2090}\sqrt{ 5}\)\(-\frac{ 23}{ 21}\)\(-\frac{ 23}{ 44}\)\(-\frac{ 23}{ 228}\)\(-\frac{ 1357}{ 2090}+\frac{ 529}{ 2090}\sqrt{ 5}\)\(0\)\(\frac{ 23}{ 140}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(1\)\(1\)\(1\)\(0\)\(1\)\(2\)
\(1\)\(1\)\(1\)\(1\)\(1\)\(0\)\(1\)\(4\)
\(2\)\(2\)\(2\)\(2\)\(2\)\(0\)\(2\)\(5\)

Note:

This is operator "6.19" from ...

Show more...  or download as   plain text  |  PDF  |  Maple  |  LaTex