Summary

You searched for: sol=1317100

Your search produced exactly one match

1

New Number: 5.50 |  AESZ: 249  |  Superseeker: -44/5 -596  |  Hash: 85592af20bbb190e37428e945664c2f3  

Degree: 5

\(5^{2} \theta^4+2^{2} 5 x\left(148\theta^4+392\theta^3+341\theta^2+145\theta+25\right)+2^{4} x^{2}\left(4096\theta^4+32128\theta^3+57016\theta^2+37920\theta+9175\right)-2^{8} x^{3}\left(6656\theta^4+7680\theta^3-36960\theta^2-49920\theta-16985\right)-2^{15} x^{4}\left(512\theta^4+4864\theta^3+9136\theta^2+6464\theta+1587\right)+2^{20} x^{5}(4\theta+5)^2(4\theta+3)^2\)

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Coefficients of the holomorphic solution: 1, -20, 684, -28496, 1317100, ...
--> OEIS
Normalized instanton numbers (n0=1): -44/5, -277/5, -596, -7236, -502128/5, ... ; Common denominator:...

Discriminant

\((1+16z)(64z+1)^2(64z-5)^2\)

Local exponents

\(-\frac{ 1}{ 16}\)\(-\frac{ 1}{ 64}\)\(0\)\(\frac{ 5}{ 64}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(\frac{ 3}{ 4}\)
\(1\)\(\frac{ 1}{ 2}\)\(0\)\(1\)\(\frac{ 3}{ 4}\)
\(1\)\(\frac{ 1}{ 2}\)\(0\)\(3\)\(\frac{ 5}{ 4}\)
\(2\)\(1\)\(0\)\(4\)\(\frac{ 5}{ 4}\)

Note:

This is operator "5.50" from ...

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