Summary

You searched for: sol=12000

Your search produced exactly one match

1

New Number: 5.66 |  AESZ: 274  |  Superseeker: 49/5 6032/15  |  Hash: 729d44a3b7b561b49603f26a25d26069  

Degree: 5

\(5^{2} \theta^4-5 x\left(757\theta^4+1298\theta^3+1049\theta^2+400\theta+60\right)+2^{2} 3^{2} x^{2}\left(5456\theta^4+17498\theta^3+22121\theta^2+11940\theta+2340\right)-2^{2} 3^{4} x^{3}\left(15128\theta^4+68040\theta^3+112171\theta^2+73845\theta+16380\right)+2^{4} 3^{8} x^{4}(2\theta+1)(216\theta^3+864\theta^2+1015\theta+356)-2^{6} 3^{10} x^{5}(2\theta+1)(3\theta+2)(3\theta+4)(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 12, 324, 12000, 548100, ...
--> OEIS
Normalized instanton numbers (n0=1): 49/5, -68/5, 6032/15, 36276/5, 350082/5, ... ; Common denominator:...

Discriminant

\(-(81z-1)(1296z^2-56z+1)(-5+36z)^2\)

Local exponents

\(0\)\(\frac{ 1}{ 81}\)\(\frac{ 7}{ 324}-\frac{ 1}{ 81}\sqrt{ 2}I\)\(\frac{ 7}{ 324}+\frac{ 1}{ 81}\sqrt{ 2}I\)\(\frac{ 5}{ 36}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(\frac{ 2}{ 3}\)
\(0\)\(1\)\(1\)\(1\)\(3\)\(\frac{ 4}{ 3}\)
\(0\)\(2\)\(2\)\(2\)\(4\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.66" from ...

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