Summary

You searched for: sol=-28

Your search produced exactly one match

1

New Number: 4.39 |  AESZ: 210  |  Superseeker: -444/5 -1501908/5  |  Hash: 155d0198a5b26de08a0c2caf680f0786  

Degree: 4

\(5^{2} \theta^4+2^{2} 5 x\left(688\theta^4+1352\theta^3+981\theta^2+305\theta+35\right)+2^{4} x^{2}\left(5856\theta^4+7008\theta^3+96\theta^2-1260\theta-265\right)+2^{10} x^{3}\left(176\theta^4+120\theta^3+69\theta^2+30\theta+5\right)+2^{12} x^{4}\left((2\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, -28, 4716, -1226800, 389349100, ...
--> OEIS
Normalized instanton numbers (n0=1): -444/5, 16653/5, -1501908/5, 199965534/5, -6573697776, ... ; Common denominator:...

Discriminant

\((256z^2+544z+1)(5+16z)^2\)

Local exponents

\(-\frac{ 17}{ 16}-\frac{ 3}{ 4}\sqrt{ 2}\)\(-\frac{ 5}{ 16}\)\(-\frac{ 17}{ 16}+\frac{ 3}{ 4}\sqrt{ 2}\)\(0\)\(s_1\)\(s_2\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(\frac{ 1}{ 2}\)
\(1\)\(3\)\(1\)\(0\)\(1\)\(1\)\(\frac{ 1}{ 2}\)
\(2\)\(4\)\(2\)\(0\)\(2\)\(2\)\(\frac{ 1}{ 2}\)

Note:

Sporadic operator. There is a second MUM point hidden at infinity; Operator AESZ 211/4.40

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