Summary

You searched for: inst=98106208

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1

New Number: 8.78 |  AESZ:  |  Superseeker: 52 48732  |  Hash: 2fb524ad6efb19e0117ae7acbd9f67b9  

Degree: 8

\(\theta^4-2^{2} x\left(184\theta^4+224\theta^3+175\theta^2+63\theta+9\right)+2^{4} 3 x^{2}\left(3472\theta^4+9664\theta^3+9864\theta^2+4264\theta+705\right)-2^{8} 3^{2} x^{3}\left(1936\theta^4+27936\theta^3+43336\theta^2+21528\theta+3933\right)-2^{16} 3^{3} x^{4}\left(1384\theta^4+524\theta^3-4555\theta^2-3404\theta-753\right)+2^{19} 3^{4} x^{5}\left(3440\theta^4+13712\theta^3-58\theta^2-3774\theta-1161\right)+2^{22} 3^{5} x^{6}\left(11312\theta^4-9888\theta^3-10808\theta^2-1608\theta+459\right)-2^{26} 3^{7} x^{7}(2\theta+1)(1336\theta^3+2772\theta^2+2234\theta+663)-2^{32} 3^{9} x^{8}(2\theta+1)(4\theta+3)(4\theta+5)(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 36, 3780, 555120, 95199300, ...
--> OEIS
Normalized instanton numbers (n0=1): 52, -399, 48732, -992750, 98106208, ... ; Common denominator:...

Discriminant

\(-(256z-1)(110592z^3+6912z^2-288z+1)(-1+96z+13824z^2)^2\)

Local exponents

≈\(-0.091906\)\(-\frac{ 1}{ 288}-\frac{ 1}{ 288}\sqrt{ 7}\)\(0\) ≈\(0.00385\)\(\frac{ 1}{ 256}\)\(-\frac{ 1}{ 288}+\frac{ 1}{ 288}\sqrt{ 7}\) ≈\(0.025556\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)\(\frac{ 3}{ 4}\)
\(1\)\(3\)\(0\)\(1\)\(1\)\(3\)\(1\)\(\frac{ 5}{ 4}\)
\(2\)\(4\)\(0\)\(2\)\(2\)\(4\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "8.78" from ...

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