Summary

You searched for: inst=7784/17

Your search produced exactly one match

1

New Number: 5.30 |  AESZ: 209  |  Superseeker: 478/17 285760/17  |  Hash: a03a0a18a8b2a4926d11e4e42b958f98  

Degree: 5

\(17^{2} \theta^4-2 17 x\left(1902\theta^4+3708\theta^3+2789\theta^2+935\theta+119\right)+2^{2} x^{2}\left(62408\theta^4+68576\theta^3-10029\theta^2-24106\theta-5661\right)-2^{2} x^{3}\left(66180\theta^4+33048\theta^3+20785\theta^2+17799\theta+4794\right)+2^{7} x^{4}(2\theta+1)(196\theta^3+498\theta^2+487\theta+169)-2^{12} x^{5}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 14, 978, 103820, 13387570, ...
--> OEIS
Normalized instanton numbers (n0=1): 478/17, 7784/17, 285760/17, 15280156/17, 1006004774/17, ... ; Common denominator:...

Discriminant

\(-(16z^3-32z^2+220z-1)(-17+32z)^2\)

Local exponents

\(0\) ≈\(0.004548\)\(\frac{ 17}{ 32}\) ≈\(0.997726-3.570079I\) ≈\(0.997726+3.570079I\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)
\(0\)\(1\)\(3\)\(1\)\(1\)\(1\)
\(0\)\(2\)\(4\)\(2\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.30" from ...

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