Summary

You searched for: inst=6446745

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1

New Number: 5.122 |  AESZ:  |  Superseeker: 19 18641/3  |  Hash: 7cc1a0411f21ffd93f1a9f6468627432  

Degree: 5

\(\theta^4+x\left(119\theta^4-194\theta^3-143\theta^2-46\theta-6\right)-2^{2} 3^{2} x^{2}\left(46\theta^4+748\theta^3+379\theta^2+150\theta+27\right)-2^{2} 3^{4} x^{3}\left(2164\theta^4+6264\theta^3+7421\theta^2+4131\theta+846\right)-2^{5} 3^{8} x^{4}(2\theta+1)(76\theta^3+222\theta^2+235\theta+85)-2^{8} 3^{12} x^{5}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 6, 162, 7620, 334530, ...
--> OEIS
Normalized instanton numbers (n0=1): 19, -170, 18641/3, -163734, 6446745, ... ; Common denominator:...

Discriminant

\(-(81z-1)(1296z^2+56z+1)(1+72z)^2\)

Local exponents

\(-\frac{ 7}{ 324}-\frac{ 1}{ 81}\sqrt{ 2}I\)\(-\frac{ 7}{ 324}+\frac{ 1}{ 81}\sqrt{ 2}I\)\(-\frac{ 1}{ 72}\)\(0\)\(\frac{ 1}{ 81}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)
\(1\)\(1\)\(3\)\(0\)\(1\)\(1\)
\(2\)\(2\)\(4\)\(0\)\(2\)\(\frac{ 3}{ 2}\)

Note:

B-Incarnation as fibre product 62211- 623--1

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