Summary

You searched for: inst=6399445/38

Your search produced exactly one match

1

New Number: 8.22 |  AESZ: 284  |  Superseeker: 241/38 8729/19  |  Hash: dbe506beab1f66a0b331f15c91b7fcde  

Degree: 8

\(2^{2} 19^{2} \theta^4-2 19 x\left(3014\theta^4+5878\theta^3+4725\theta^2+1786\theta+266\right)+x^{2}\left(402002+1810054\theta+3057079\theta^2+2305502\theta^3+689717\theta^4\right)-x^{3}\left(1576582+6295992\theta+9142457\theta^2+5812350\theta^3+1438808\theta^4\right)+x^{4}\left(663471+3375833\theta+6297445\theta^2+5075392\theta^3+1395491\theta^4\right)+x^{5}\left(52928-604005\theta-2407768\theta^2-2657224\theta^3-834163\theta^4\right)-x^{6}\left(4832-148359\theta-572576\theta^2-692484\theta^3-277543\theta^4\right)-11 x^{7}\left(4625\theta^4+9100\theta^3+6395\theta^2+1845\theta+178\right)-11^{2} x^{8}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 7, 163, 5767, 247651, ...
--> OEIS
Normalized instanton numbers (n0=1): 241/38, 1353/38, 8729/19, 150334/19, 6399445/38, ... ; Common denominator:...

Discriminant

\(-(-1+78z-374z^2+425z^3+z^4)(38-25z+11z^2)^2\)

Local exponents

\(0\)\(\frac{ 25}{ 22}-\frac{ 1}{ 22}\sqrt{ 1047}I\)\(\frac{ 25}{ 22}+\frac{ 1}{ 22}\sqrt{ 1047}I\)\(#ND+#NDI\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(1\)
\(0\)\(1\)\(1\)\(1\)\(1\)
\(0\)\(3\)\(3\)\(1\)\(1\)
\(0\)\(4\)\(4\)\(2\)\(1\)

Note:

This operator has a second MUM-point at infinity, corresponding to operator 8.23

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