Summary

You searched for: inst=5568700/19

Your search produced exactly one match

1

New Number: 6.4 |  AESZ:  |  Superseeker: 370/19 140636/19  |  Hash: 0f3ddf420018e2870561a3e9fd2551cc  

Degree: 6

\(19^{2} \theta^4-19 x\left(4333\theta^4+6212\theta^3+4778\theta^2+1672\theta+228\right)+x^{2}\left(4307495\theta^4+7600484\theta^3+6216406\theta^2+2802424\theta+530556\right)-x^{3}\left(93729369\theta^4+213316800\theta^3+236037196\theta^2+125748612\theta+25260804\right)+2^{2} x^{4}\left(240813800\theta^4+778529200\theta^3+1041447759\theta^2+631802809\theta+138510993\right)-2^{2} 409 x^{5}(\theta+1)(2851324\theta^3+10035516\theta^2+11221241\theta+3481470)+2^{2} 3^{2} 19^{2} 409^{2} x^{6}(\theta+1)(\theta+2)(2\theta+1)(2\theta+5)\)

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Coefficients of the holomorphic solution: 1, 12, 588, 46200, 4446540, ...
--> OEIS
Normalized instanton numbers (n0=1): 370/19, 276, 140636/19, 5568700/19, 277119292/19, ... ; Common denominator:...

Discriminant

\((9z-1)(5776z^3-1920z^2+176z-1)(-19+409z)^2\)

Local exponents

\(0\) ≈\(0.006077\)\(\frac{ 19}{ 409}\)\(\frac{ 1}{ 9}\) ≈\(0.163166-0.043179I\) ≈\(0.163166+0.043179I\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)\(1\)
\(0\)\(1\)\(3\)\(1\)\(1\)\(1\)\(2\)
\(0\)\(2\)\(4\)\(2\)\(2\)\(2\)\(\frac{ 5}{ 2}\)

Note:

This is operator "6.4" from ...

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