Summary

You searched for: inst=48

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1

New Number: 2.15 |  AESZ: 38  |  Superseeker: 48 73328  |  Hash: 9ce26bb7405c3b98d8aeae5b1102c611  

Degree: 2

\(\theta^4-2^{4} x(4\theta+1)(4\theta+3)(3\theta^2+3\theta+1)+2^{9} x^{2}(4\theta+1)(4\theta+3)(4\theta+5)(4\theta+7)\)

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Coefficients of the holomorphic solution: 1, 48, 8400, 2069760, 609008400, ...
--> OEIS
Normalized instanton numbers (n0=1): 48, 998, 73328, 7388135, 857248528, ... ; Common denominator:...

Discriminant

\((512z-1)(256z-1)\)

Local exponents

\(0\)\(\frac{ 1}{ 512}\)\(\frac{ 1}{ 256}\)\(\infty\)
\(0\)\(0\)\(0\)\(\frac{ 1}{ 4}\)
\(0\)\(1\)\(1\)\(\frac{ 3}{ 4}\)
\(0\)\(1\)\(1\)\(\frac{ 5}{ 4}\)
\(0\)\(2\)\(2\)\(\frac{ 7}{ 4}\)

Note:

Hadamard product $C\ast d$

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2

New Number: 2.28 |  AESZ: 49  |  Superseeker: 48 2864  |  Hash: 0a357a8c4fd703ab062148eadcd94daa  

Degree: 2

\(\theta^4-2^{2} 3 x(2\theta+1)^2(18\theta^2+18\theta+7)+2^{4} 3^{6} x^{2}(2\theta+1)^2(2\theta+3)^2\)

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Coefficients of the holomorphic solution: 1, 84, 17820, 4868400, 1499003100, ...
--> OEIS
Normalized instanton numbers (n0=1): 48, -438, 2864, 77958, -4942032, ... ; Common denominator:...

Discriminant

\((432z-1)^2\)

Local exponents

\(0\)\(\frac{ 1}{ 432}\)\(\infty\)
\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(\frac{ 1}{ 3}\)\(\frac{ 1}{ 2}\)
\(0\)\(\frac{ 2}{ 3}\)\(\frac{ 3}{ 2}\)
\(0\)\(1\)\(\frac{ 3}{ 2}\)

Note:

Hadamard product $A \ast$

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3

New Number: 4.65 |  AESZ:  |  Superseeker: 48 -9104  |  Hash: 5ec2790b5eda514313634b7aeb0a295c  

Degree: 4

\(\theta^4-2^{4} x\left(5\theta^4+34\theta^3+25\theta^2+8\theta+1\right)+2^{11} x^{2}\left(5\theta^4+47\theta^3+90\theta^2+47\theta+8\right)+2^{16} x^{3}\left(51\theta^4+192\theta^3+155\theta^2+48\theta+5\right)+2^{23} x^{4}\left((2\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 16, 144, -70400, -9858800, ...
--> OEIS
Normalized instanton numbers (n0=1): 48, -1298, -9104, 387230, 102374160, ... ; Common denominator:...

Discriminant

\((32768z^2-208z+1)(1+64z)^2\)

Local exponents

\(-\frac{ 1}{ 64}\)\(0\)\(s_1\)\(s_2\)\(\frac{ 13}{ 4096}-\frac{ 7}{ 4096}\sqrt{ 7}I\)\(\frac{ 13}{ 4096}+\frac{ 7}{ 4096}\sqrt{ 7}I\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)\(\frac{ 1}{ 2}\)
\(3\)\(0\)\(1\)\(1\)\(1\)\(1\)\(\frac{ 1}{ 2}\)
\(4\)\(0\)\(2\)\(2\)\(2\)\(2\)\(\frac{ 1}{ 2}\)

Note:

Sporadic Operator. There is a second MUM-point hiding at infinity,
corresponding to Operator AESZ 295/4.64

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4

New Number: 5.120 |  AESZ:  |  Superseeker: 48 171120  |  Hash: 3eb6b52ff225f7b2f94716d73344b578  

Degree: 5

\(\theta^4-2^{4} x\left(41\theta^4+34\theta^3+25\theta^2+8\theta+1\right)+2^{10} x^{2}\left(126\theta^4+108\theta^3+33\theta^2+6\theta+1\right)-2^{14} x^{3}\left(564\theta^4+504\theta^3+429\theta^2+195\theta+34\right)+2^{21} x^{4}(2\theta+1)(44\theta^3+78\theta^2+59\theta+17)-2^{28} x^{5}(2\theta+1)(\theta+1)^2(2\theta+3)\)

Maple   LaTex

Coefficients of the holomorphic solution: 1, 16, 1680, 298240, 64975120, ...
--> OEIS
Normalized instanton numbers (n0=1): 48, 2286, 171120, 17540830, 2229934864, ... ; Common denominator:...

Discriminant

\(-(16z-1)(4096z^2-384z+1)(-1+128z)^2\)

Local exponents

\(0\)\(\frac{ 3}{ 64}-\frac{ 1}{ 32}\sqrt{ 2}\)\(\frac{ 1}{ 128}\)\(\frac{ 1}{ 16}\)\(\frac{ 3}{ 64}+\frac{ 1}{ 32}\sqrt{ 2}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)
\(0\)\(1\)\(3\)\(1\)\(1\)\(1\)
\(0\)\(2\)\(4\)\(2\)\(2\)\(\frac{ 3}{ 2}\)

Note:

B-Incarnation as fibre product 62211- x 821--1

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5

New Number: 5.89 |  AESZ: 329  |  Superseeker: 48 25200  |  Hash: 8c526b3b825d5ad6a3d0fb83ee4e6059  

Degree: 5

\(\theta^4-2^{4} x\left(8\theta^4+34\theta^3+25\theta^2+8\theta+1\right)-2^{8} x^{2}\left(87\theta^4+150\theta^3+32\theta^2-2\theta-1\right)-2^{12} x^{3}\left(202\theta^4+240\theta^3+211\theta^2+102\theta+19\right)-2^{16} 3 x^{4}(2\theta+1)(22\theta^3+45\theta^2+38\theta+12)-2^{20} 3^{2} x^{5}(2\theta+1)(\theta+1)^2(2\theta+3)\)

Maple   LaTex

Coefficients of the holomorphic solution: 1, 16, 1200, 136960, 19010320, ...
--> OEIS
Normalized instanton numbers (n0=1): 48, 270, 25200, 968066, 80892688, ... ; Common denominator:...

Discriminant

\(-(16384z^3+3072z^2+224z-1)(1+48z)^2\)

Local exponents

≈\(-0.095858-0.072741I\) ≈\(-0.095858+0.072741I\)\(-\frac{ 1}{ 48}\)\(0\) ≈\(0.004215\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)
\(1\)\(1\)\(3\)\(0\)\(1\)\(1\)
\(2\)\(2\)\(4\)\(0\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.89" from ...

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6

New Number: 12.12 |  AESZ:  |  Superseeker: 48 3184  |  Hash: 2b1c995b5f2826ce90fc016ad86fd66f  

Degree: 12

\(\theta^4-2^{4} x\left(27\theta^4+42\theta^3+37\theta^2+16\theta+3\right)+2^{9} x^{2}\left(139\theta^4+430\theta^3+579\theta^2+376\theta+103\right)-2^{14} x^{3}\left(369\theta^4+1638\theta^3+2992\theta^2+2481\theta+819\right)+2^{19} x^{4}\left(667\theta^4+2870\theta^3+6158\theta^2+6571\theta+2559\right)-2^{24} x^{5}\left(1263\theta^4+3066\theta^3+2692\theta^2+4295\theta+2110\right)+2^{29} 3 x^{6}\left(787\theta^4+1842\theta^3-1598\theta^2-3339\theta-1652\right)-2^{34} x^{7}\left(3087\theta^4+9750\theta^3+2942\theta^2-13117\theta-9816\right)+2^{39} x^{8}\left(3227\theta^4+6254\theta^3+14286\theta^2+4793\theta-1948\right)-2^{44} x^{9}\left(3906\theta^4+1440\theta^3+5279\theta^2+7593\theta+3747\right)+2^{49} x^{10}\left(3896\theta^4+6208\theta^3+3391\theta^2+725\theta+525\right)-2^{54} 5 x^{11}\left(408\theta^4+1536\theta^3+2230\theta^2+1460\theta+361\right)+2^{59} 5^{2} x^{12}\left((2\theta+3)^4\right)\)

Maple   LaTex

Coefficients of the holomorphic solution: 1, 48, 2704, 179968, 14147856, ...
--> OEIS
Normalized instanton numbers (n0=1): 48, 46, 3184, 409910, -3351792, ... ; Common denominator:...

Discriminant

\((16z-1)(32z-1)(4096z^2-192z+1)(64z-1)^2(163840z^3+1024z^2+32z-1)^2\)

Local exponents

≈\(-0.009802-0.019I\) ≈\(-0.009802+0.019I\)\(0\)\(\frac{ 3}{ 128}-\frac{ 1}{ 128}\sqrt{ 5}\) ≈\(0.013353\)\(\frac{ 1}{ 64}\)\(\frac{ 1}{ 32}\)\(\frac{ 3}{ 128}+\frac{ 1}{ 128}\sqrt{ 5}\)\(\frac{ 1}{ 16}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 3}{ 2}\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(\frac{ 3}{ 2}\)
\(3\)\(3\)\(0\)\(1\)\(3\)\(1\)\(1\)\(1\)\(1\)\(\frac{ 3}{ 2}\)
\(4\)\(4\)\(0\)\(2\)\(4\)\(1\)\(2\)\(2\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "12.12" from ...

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7

New Number: 14.7 |  AESZ:  |  Superseeker: 48 3184  |  Hash: 9e304ff532f3cfafc29dfac77fdff067  

Degree: 14

\(\theta^4-2^{4} x\left(35\theta^4+50\theta^3+49\theta^2+24\theta+5\right)+2^{9} x^{2}\left(255\theta^4+722\theta^3+1027\theta^2+740\theta+227\right)-2^{14} x^{3}\left(1033\theta^4+4298\theta^3+7994\theta^2+7243\theta+2695\right)+2^{19} x^{4}\left(2699\theta^4+13730\theta^3+30984\theta^2+33699\theta+14443\right)-2^{24} x^{5}\left(5407\theta^4+26718\theta^3+63946\theta^2+80619\theta+38786\right)+2^{29} x^{6}\left(10081\theta^4+39658\theta^3+68604\theta^2+85851\theta+43438\right)-2^{34} x^{7}\left(17583\theta^4+63666\theta^3+51252\theta^2-1045\theta-18966\right)+2^{39} x^{8}\left(25019\theta^4+98594\theta^3+101972\theta^2-44371\theta-87630\right)-2^{44} x^{9}\left(29162\theta^4+103060\theta^3+189337\theta^2+75677\theta-39871\right)+2^{49} x^{10}\left(32428\theta^4+78424\theta^3+166293\theta^2+155877\theta+49943\right)-2^{54} x^{11}\left(33248\theta^4+85104\theta^3+119906\theta^2+105882\theta+49279\right)+2^{59} x^{12}\left(24144\theta^4+97280\theta^3+159468\theta^2+125460\theta+41819\right)-2^{67} 5 x^{13}\left(244\theta^4+1456\theta^3+3353\theta^2+3523\theta+1423\right)+2^{75} 5^{2} x^{14}\left((\theta+2)^4\right)\)

Maple   LaTex

Coefficients of the holomorphic solution: 1, 80, 5776, 422144, 32579856, ...
--> OEIS
Normalized instanton numbers (n0=1): 48, 46, 3184, 409910, -3351792, ... ; Common denominator:...

Discriminant

\((16z-1)(32z-1)(4096z^2-192z+1)(163840z^3+1024z^2+32z-1)^2(64z-1)^4\)

Local exponents

≈\(-0.009802-0.019I\) ≈\(-0.009802+0.019I\)\(0\)\(\frac{ 3}{ 128}-\frac{ 1}{ 128}\sqrt{ 5}\) ≈\(0.013353\)\(\frac{ 1}{ 64}\)\(\frac{ 1}{ 32}\)\(\frac{ 3}{ 128}+\frac{ 1}{ 128}\sqrt{ 5}\)\(\frac{ 1}{ 16}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(-\frac{ 1}{ 2}\)\(0\)\(0\)\(0\)\(2\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(-\frac{ 1}{ 2}\)\(1\)\(1\)\(1\)\(2\)
\(3\)\(3\)\(0\)\(1\)\(3\)\(\frac{ 1}{ 2}\)\(1\)\(1\)\(1\)\(2\)
\(4\)\(4\)\(0\)\(2\)\(4\)\(\frac{ 1}{ 2}\)\(2\)\(2\)\(2\)\(2\)

Note:

This is operator "14.7" from ...

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