Summary

You searched for: inst=323686899951

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1

New Number: 5.125 |  AESZ:  |  Superseeker: 229 10128562/3  |  Hash: ce147b64cc67dee1204a2d16f6ac4210  

Degree: 5

\(\theta^4-x\left(1217\theta^4+2050\theta^3+1437\theta^2+412\theta+44\right)+2^{5} x^{2}(\theta+1)(4550\theta^3-186\theta^2-899\theta-171)-2^{8} x^{3}\left(18484\theta^4+3192\theta^3+1005\theta^2+1107\theta+258\right)+2^{14} x^{4}(2\theta+1)(268\theta^3+414\theta^2+267\theta+65)-2^{20} x^{5}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 44, 14532, 7508960, 4749338020, ...
--> OEIS
Normalized instanton numbers (n0=1): 229, 18542, 10128562/3, 938391582, 323686899951, ... ; Common denominator:...

Discriminant

\(-(z-1)(1024z^2-1088z+1)(-1+64z)^2\)

Local exponents

\(0\)\(\frac{ 17}{ 32}-\frac{ 3}{ 8}\sqrt{ 2}\)\(\frac{ 1}{ 64}\)\(1\)\(\frac{ 17}{ 32}+\frac{ 3}{ 8}\sqrt{ 2}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)
\(0\)\(1\)\(3\)\(1\)\(1\)\(1\)
\(0\)\(2\)\(4\)\(2\)\(2\)\(\frac{ 3}{ 2}\)

Note:

B-Incarnation as fibre product 62211- x 362--1

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