Summary

You searched for: inst=30735

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1

New Number: 6.5 |  AESZ:  |  Superseeker: -11 -3422/3  |  Hash: 6a4aeb5833b7673c962d5598842d3f2c  

Degree: 6

\(\theta^4-x\left(12+64\theta+125\theta^2+122\theta^3+61\theta^4\right)-2^{3} x^{2}\left(193\theta^4+772\theta^3+1033\theta^2+522\theta+72\right)+2^{9} 3 x^{3}\left(146\theta^4+876\theta^3+1838\theta^2+1572\theta+405\right)-2^{12} 3^{2} x^{4}\left(204\theta^4+1632\theta^3+4449\theta^2+4740\theta+1400\right)+2^{16} 3^{3} x^{5}(16\theta^2+80\theta+35)(2\theta+5)^2-2^{19} 3^{4} x^{6}(2\theta+11)(2\theta+7)(2\theta+5)(2\theta+1)\)

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Coefficients of the holomorphic solution: 1, 12, 324, 5760, 215460, ...
--> OEIS
Normalized instanton numbers (n0=1): -11, 68, -3422/3, 30735, -1014993, ... ; Common denominator:...

Discriminant

\(-(24z-1)(27648z^3-1728z^2+27z+1)(-1+32z)^2\)

Local exponents

≈\(-0.016119\)\(0\)\(\frac{ 1}{ 32}\) ≈\(0.03931-0.026431I\) ≈\(0.03931+0.026431I\)\(\frac{ 1}{ 24}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(0\)\(\frac{ 1}{ 2}\)\(1\)\(1\)\(1\)\(\frac{ 5}{ 2}\)
\(1\)\(0\)\(\frac{ 1}{ 2}\)\(1\)\(1\)\(1\)\(\frac{ 7}{ 2}\)
\(2\)\(0\)\(1\)\(2\)\(2\)\(2\)\(\frac{ 11}{ 2}\)

Note:

This is operator "6.5" from ...

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