Summary

You searched for: inst=2668/3

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New Number: 5.93 |  AESZ: 333  |  Superseeker: 1 2668/3  |  Hash: dc274781605ee4262d8745e3fa3a8057  

Degree: 5

\(\theta^4+x\theta^2(71\theta^2-2\theta-1)+2^{3} 3 x^{2}\left(154\theta^4+334\theta^3+461\theta^2+248\theta+48\right)+2^{6} 3^{2} x^{3}(5\theta+3)(31\theta^3+39\theta^2-25\theta-21)+2^{9} 3^{4} x^{4}(2\theta+1)(2\theta^3-33\theta^2-56\theta-24)-2^{12} 3^{6} x^{5}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 0, -72, 1440, 22680, ...
--> OEIS
Normalized instanton numbers (n0=1): 1, -66, 2668/3, -2774, -167786, ... ; Common denominator:...

Discriminant

\(-(9z-1)(2304z^2+32z+1)(1+24z)^2\)

Local exponents

\(-\frac{ 1}{ 24}\)\(-\frac{ 1}{ 144}-\frac{ 1}{ 72}\sqrt{ 2}I\)\(-\frac{ 1}{ 144}+\frac{ 1}{ 72}\sqrt{ 2}I\)\(0\)\(\frac{ 1}{ 9}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)
\(3\)\(1\)\(1\)\(0\)\(1\)\(1\)
\(4\)\(2\)\(2\)\(0\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.93" from ...

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