Summary

You searched for: inst=247828991/2

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1

New Number: 5.126 |  AESZ:  |  Superseeker: 110 729096  |  Hash: 511069e41e6328e47a1ea996049096b4  

Degree: 5

\(\theta^4-x\left(881\theta^4+1222\theta^3+878\theta^2+267\theta+30\right)+3 x^{2}\left(50601\theta^4+60024\theta^3+17189\theta^2+280\theta-340\right)-3^{2} 5 x^{3}\left(195867\theta^4+207846\theta^3+142719\theta^2+49068\theta+6316\right)+2^{2} 3^{4} 5^{2} x^{4}(3\theta+1)(3\theta+2)(1902\theta^2+1767\theta+386)+2^{2} 3^{6} 5^{4} x^{5}(3\theta+1)(3\theta+2)(3\theta+4)(3\theta+5)\)

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Coefficients of the holomorphic solution: 1, 30, 6210, 2004240, 789638850, ...
--> OEIS
Normalized instanton numbers (n0=1): 110, 12935/2, 729096, 247828991/2, 26419290920, ... ; Common denominator:...

Discriminant

\((675z-1)(27z-1)(z+1)(-1+90z)^2\)

Local exponents

\(-1\)\(0\)\(\frac{ 1}{ 675}\)\(\frac{ 1}{ 90}\)\(\frac{ 1}{ 27}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 3}\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(\frac{ 2}{ 3}\)
\(1\)\(0\)\(1\)\(3\)\(1\)\(\frac{ 4}{ 3}\)
\(2\)\(0\)\(2\)\(4\)\(2\)\(\frac{ 5}{ 3}\)

Note:

Operator London 18.
B-Incarnation: Laurent-polynomial.

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