Summary

You searched for: inst=2362/29

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1

New Number: 5.24 |  AESZ: 195  |  Superseeker: 285/29 40626/29  |  Hash: 49a600431b3e9aaa9d9d6947f8df7d2b  

Degree: 5

\(29^{2} \theta^4-29 x\left(3026\theta^4+5848\theta^3+4577\theta^2+1653\theta+232\right)+x^{2}\left(5568+57768\theta+239159\theta^2+424220\theta^3+258647\theta^4\right)-x^{3}\left(76560+336864\theta+581647\theta^2+532614\theta^3+272743\theta^4\right)+2^{2} 17 x^{4}\left(1922\theta^4+6193\theta^3+8121\theta^2+4894\theta+1112\right)-2^{2} 3 17^{2} x^{5}(\theta+1)^2(3\theta+2)(3\theta+4)\)

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Coefficients of the holomorphic solution: 1, 8, 264, 13040, 778840, ...
--> OEIS
Normalized instanton numbers (n0=1): 285/29, 2362/29, 40626/29, 997476/29, 30096841/29, ... ; Common denominator:...

Discriminant

\(-(27z^3-67z^2+102z-1)(-29+34z)^2\)

Local exponents

\(0\) ≈\(0.009868\)\(\frac{ 29}{ 34}\) ≈\(1.235807-1.492036I\) ≈\(1.235807+1.492036I\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 2}{ 3}\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)
\(0\)\(1\)\(3\)\(1\)\(1\)\(1\)
\(0\)\(2\)\(4\)\(2\)\(2\)\(\frac{ 4}{ 3}\)

Note:

This is operator "5.24" from ...

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