Summary

You searched for: inst=1830480

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1

New Number: 4.40 |  AESZ: 211  |  Superseeker: -2400 -2956977632  |  Hash: c923c78e33e72a3a2b294bf3f2749298  

Degree: 4

\(\theta^4+2^{4} x\left(704\theta^4+928\theta^3+612\theta^2+148\theta+13\right)+2^{12} x^{2}\left(5856\theta^4+4704\theta^3-1632\theta^2-972\theta-121\right)+2^{20} 5 x^{3}\left(2752\theta^4+96\theta^3-60\theta^2+24\theta+7\right)+2^{28} 5^{2} x^{4}\left((2\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, -208, 531216, -2168300800, 10900554288400, ...
--> OEIS
Normalized instanton numbers (n0=1): -2400, 1830480, -2956977632, 7117422755016, -21319886408804640, ... ; Common denominator:...

Discriminant

\((65536z^2+8704z+1)(1+1280z)^2\)

Local exponents

\(-\frac{ 17}{ 256}-\frac{ 3}{ 64}\sqrt{ 2}\)\(-\frac{ 1}{ 1280}\)\(-\frac{ 17}{ 256}+\frac{ 3}{ 64}\sqrt{ 2}\)\(0\)\(s_1\)\(s_2\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(\frac{ 1}{ 2}\)
\(1\)\(3\)\(1\)\(0\)\(1\)\(1\)\(\frac{ 1}{ 2}\)
\(2\)\(4\)\(2\)\(0\)\(2\)\(2\)\(\frac{ 1}{ 2}\)

Note:

Sporadic Operator. There is a second MUM point hidden at infinity. That corresponds to Operator AESZ210/

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