Summary

You searched for: inst=173044/5

Your search produced exactly one match

1

New Number: 5.28 |  AESZ: 203  |  Superseeker: -13/5 -6729/5  |  Hash: dfab012366b4bc6f7af83dc79f28b802  

Degree: 5

\(5^{2} \theta^4+5 x\theta(499\theta^3+86\theta^2+53\theta+10)+2^{4} x^{2}\left(1649\theta^4-13183\theta^3-19776\theta^2-11020\theta-2200\right)-2^{6} x^{3}\left(39521\theta^4+162000\theta^3+142095\theta^2+51540\theta+6540\right)-2^{11} 19 x^{4}\left(1370\theta^4+2860\theta^3+2449\theta^2+1019\theta+174\right)-2^{16} 19^{2} x^{5}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 0, 88, -1728, 99576, ...
--> OEIS
Normalized instanton numbers (n0=1): -13/5, 427/5, -6729/5, 173044/5, -952275, ... ; Common denominator:...

Discriminant

\(-(32z-1)(32z^2+71z+1)(5+152z)^2\)

Local exponents

\(-\frac{ 71}{ 64}-\frac{ 17}{ 64}\sqrt{ 17}\)\(-\frac{ 5}{ 152}\)\(-\frac{ 71}{ 64}+\frac{ 17}{ 64}\sqrt{ 17}\)\(0\)\(\frac{ 1}{ 32}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)
\(1\)\(3\)\(1\)\(0\)\(1\)\(1\)
\(2\)\(4\)\(2\)\(0\)\(2\)\(1\)

Note:

There is a second MUM-point at infinity, corresponding to Operator AESZ 202 /5.27

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