Summary

You searched for: inst=17175

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1

New Number: 5.103 |  AESZ: 354  |  Superseeker: 25 17175  |  Hash: 0d4263e8c85dceb5c51f8614f7c1bc79  

Degree: 5

\(\theta^4-5 x\left(170\theta^4+160\theta^3+125\theta^2+45\theta+6\right)+3 5^{3} x^{2}\left(725\theta^4+1220\theta^3+1105\theta^2+460\theta+68\right)-3^{2} 5^{5} x^{3}\left(1421\theta^4+3186\theta^3+3053\theta^2+1272\theta+188\right)+2^{2} 3^{3} 5^{7} x^{4}(3\theta+1)(3\theta+2)(34\theta^2+61\theta+36)-2^{2} 3^{4} 5^{9} x^{5}(3\theta+1)(3\theta+2)(3\theta+4)(3\theta+5)\)

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Coefficients of the holomorphic solution: 1, 30, 3150, 462000, 78828750, ...
--> OEIS
Normalized instanton numbers (n0=1): 25, 2175/4, 17175, 351250, 23000351/5, ... ; Common denominator:...

Discriminant

\(-(2278125z^3-84375z^2+550z-1)(-1+150z)^2\)

Local exponents

\(0\) ≈\(0.003863-0.000232I\) ≈\(0.003863+0.000232I\)\(\frac{ 1}{ 150}\) ≈\(0.029311\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 3}\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(\frac{ 2}{ 3}\)
\(0\)\(1\)\(1\)\(3\)\(1\)\(\frac{ 4}{ 3}\)
\(0\)\(2\)\(2\)\(4\)\(2\)\(\frac{ 5}{ 3}\)

Note:

This is operator "5.103" from ...

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