Summary

You searched for: inst=166/5

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1

New Number: 5.36 |  AESZ: 219  |  Superseeker: 166/5 360988/15  |  Hash: b7068bb339f61ebd7c591b7be3fe5893  

Degree: 5

\(5^{2} \theta^4-2 5 x\left(464\theta^4+1036\theta^3+763\theta^2+245\theta+30\right)-2^{2} 3^{2} x^{2}\left(7064\theta^4+22472\theta^3+26699\theta^2+13200\theta+2340\right)-2^{4} 3^{4} x^{3}\left(3440\theta^4+13320\theta^3+18784\theta^2+10665\theta+2070\right)-2^{6} 3^{8} x^{4}(19\theta^2+59\theta+45)(2\theta+1)^2-2^{8} 3^{9} x^{5}(2\theta+1)^2(2\theta+3)^2\)

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Coefficients of the holomorphic solution: 1, 12, 972, 109200, 14949900, ...
--> OEIS
Normalized instanton numbers (n0=1): 166/5, 638, 360988/15, 7222128/5, 524377242/5, ... ; Common denominator:...

Discriminant

\(-(16z+1)(3888z^2+216z-1)(5+36z)^2\)

Local exponents

\(-\frac{ 5}{ 36}\)\(-\frac{ 1}{ 16}\)\(-\frac{ 1}{ 36}-\frac{ 1}{ 54}\sqrt{ 3}\)\(0\)\(-\frac{ 1}{ 36}+\frac{ 1}{ 54}\sqrt{ 3}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(\frac{ 1}{ 2}\)
\(3\)\(1\)\(1\)\(0\)\(1\)\(\frac{ 3}{ 2}\)
\(4\)\(2\)\(2\)\(0\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.36" from ...

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