Summary

You searched for: inst=1532/13

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1

New Number: 5.98 |  AESZ: 341  |  Superseeker: 87/13 21589/13  |  Hash: eed12a307d671fcf681b9d108c5e4c9e  

Degree: 5

\(13^{2} \theta^4-13 x\left(1217\theta^4+1474\theta^3+1127\theta^2+390\theta+52\right)-2^{4} x^{2}\left(5134\theta^4+83956\theta^3+142024\theta^2+83616\theta+16575\right)+2^{6} x^{3}\left(142492\theta^4+565032\theta^3+604615\theta^2+269841\theta+44070\right)-2^{11} 5 x^{4}(2\theta+1)(4324\theta^3+10698\theta^2+9903\theta+3110)+2^{16} 3 5^{2} x^{5}(2\theta+1)(3\theta+2)(3\theta+4)(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 4, 180, 7600, 433300, ...
--> OEIS
Normalized instanton numbers (n0=1): 87/13, 1532/13, 21589/13, 589110/13, 17749920/13, ... ; Common denominator:...

Discriminant

\((27z+1)(256z^2-96z+1)(-13+160z)^2\)

Local exponents

\(-\frac{ 1}{ 27}\)\(0\)\(\frac{ 3}{ 16}-\frac{ 1}{ 8}\sqrt{ 2}\)\(\frac{ 13}{ 160}\)\(\frac{ 3}{ 16}+\frac{ 1}{ 8}\sqrt{ 2}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(\frac{ 2}{ 3}\)
\(1\)\(0\)\(1\)\(3\)\(1\)\(\frac{ 4}{ 3}\)
\(2\)\(0\)\(2\)\(4\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.98" from ...

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