Summary

You searched for: inst=153/5

Your search produced exactly one match

1

New Number: 5.56 |  AESZ: 262  |  Superseeker: -28/5 -1268/5  |  Hash: 4899f97226a5ec3b1ded2994470e9fdc  

Degree: 5

\(5^{2} \theta^4+2^{2} 5 x\left(136\theta^4+224\theta^3+197\theta^2+85\theta+15\right)+2^{4} x^{2}\left(5584\theta^4+16192\theta^3+21924\theta^2+14800\theta+3955\right)+2^{11} x^{3}\left(608\theta^4+2280\theta^3+3642\theta^2+2745\theta+780\right)+2^{14} x^{4}\left(464\theta^4+1888\theta^3+2956\theta^2+2012\theta+501\right)+2^{24} x^{5}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, -12, 236, -6384, 217836, ...
--> OEIS
Normalized instanton numbers (n0=1): -28/5, 153/5, -1268/5, 18598/5, -320048/5, ... ; Common denominator:...

Discriminant

\((1+64z)(32z+5)^2(16z+1)^2\)

Local exponents

\(-\frac{ 5}{ 32}\)\(-\frac{ 1}{ 16}\)\(-\frac{ 1}{ 64}\)\(0\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(0\)\(1\)\(0\)\(1\)
\(3\)\(1\)\(1\)\(0\)\(1\)
\(4\)\(1\)\(2\)\(0\)\(1\)

Note:

There is a second MUM-point at infinity,
corresponding to the Operator AESZ 263/5.57

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