Summary

You searched for: inst=1376205/4

Your search produced exactly one match

1

New Number: 8.32 |  AESZ: 317  |  Superseeker: 69/4 14365/12  |  Hash: cda8cce31025f51636125bea67a820d1  

Degree: 8

\(2^{4} \theta^4-2^{2} 3 x\left(162\theta^4+414\theta^3+335\theta^2+128\theta+20\right)+3^{3} x^{2}\left(1219\theta^4+10906\theta^3+18963\theta^2+11824\theta+2708\right)+3^{5} 5 x^{3}\left(922\theta^4+162\theta^3-6403\theta^2-6576\theta-1964\right)-3^{7} x^{4}\left(10358\theta^4+58054\theta^3+62251\theta^2+29672\theta+4907\right)-3^{9} 5 x^{5}\left(1519\theta^4-1262\theta^3+1371\theta^2+4264\theta+1802\right)+2 3^{11} 5 x^{6}\left(1727\theta^4+3702\theta^3+3085\theta^2+882\theta+17\right)-3^{13} 5^{2} x^{7}\left(239\theta^4+460\theta^3+314\theta^2+84\theta+6\right)-3^{16} 5^{2} x^{8}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 15, 459, 19545, 1019259, ...
--> OEIS
Normalized instanton numbers (n0=1): 69/4, -30, 14365/12, 3015/2, 1376205/4, ... ; Common denominator:...

Discriminant

\(-(27z-1)(243z^3+2214z^2-117z+1)(-4-45z+405z^2)^2\)

Local exponents

≈\(-9.163702\)\(\frac{ 1}{ 18}-\frac{ 1}{ 90}\sqrt{ 105}\)\(0\) ≈\(0.010727\)\(\frac{ 1}{ 27}\) ≈\(0.041864\)\(\frac{ 1}{ 18}+\frac{ 1}{ 90}\sqrt{ 105}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)
\(1\)\(3\)\(0\)\(1\)\(1\)\(1\)\(3\)\(1\)
\(2\)\(4\)\(0\)\(2\)\(2\)\(2\)\(4\)\(1\)

Note:

This operator has a second MUM-point at infininty corresponding to operator 8.31

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