Summary

You searched for: inst=1370/7

Your search produced exactly one match

1

New Number: 9.2 |  AESZ:  |  Superseeker: 9/7 49/3  |  Hash: 356d4564e48d7a04e815fa223b6ccc46  

Degree: 9

\(7^{2} \theta^4+7 x\theta(165\theta^3-102\theta^2-65\theta-14)-2^{3} x^{2}\left(920\theta^4+11726\theta^3+15277\theta^2+9478\theta+2352\right)-2^{4} 3^{2} x^{3}\left(4035\theta^4+19554\theta^3+29157\theta^2+20706\theta+5761\right)-2^{8} 3^{2} x^{4}\left(4156\theta^4+17951\theta^3+28198\theta^2+21045\theta+6096\right)-2^{11} 3^{3} x^{5}\left(1538\theta^4+6560\theta^3+10755\theta^2+8234\theta+2420\right)-2^{13} 3^{4} x^{6}\left(695\theta^4+3051\theta^3+5285\theta^2+4191\theta+1259\right)-2^{14} 3^{5} x^{7}\left(385\theta^4+1802\theta^3+3319\theta^2+2754\theta+855\right)-2^{18} 3^{6} x^{8}(\theta+1)^2(15\theta^2+48\theta+43)-2^{20} 3^{7} x^{9}(\theta+1)^2(\theta+2)^2\)

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Coefficients of the holomorphic solution: 1, 0, 24, 144, 3240, ...
--> OEIS
Normalized instanton numbers (n0=1): 9/7, 47/7, 49/3, 1370/7, 10063/7, ... ; Common denominator:...

Discriminant

\(-(8z+1)(24z-1)(3z+1)(4z+1)(12z+1)(7+72z+288z^2)^2\)

Local exponents

\(-\frac{ 1}{ 3}\)\(-\frac{ 1}{ 4}\)\(-\frac{ 1}{ 8}-\frac{ 1}{ 24}\sqrt{ 5}I\)\(-\frac{ 1}{ 8}\)\(-\frac{ 1}{ 8}+\frac{ 1}{ 24}\sqrt{ 5}I\)\(-\frac{ 1}{ 12}\)\(0\)\(\frac{ 1}{ 24}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(1\)\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)
\(1\)\(1\)\(3\)\(1\)\(3\)\(1\)\(0\)\(1\)\(2\)
\(2\)\(2\)\(4\)\(2\)\(4\)\(2\)\(0\)\(2\)\(2\)

Note:

This is operator "9.2" from ...

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