Summary

You searched for: inst=132/5

Your search produced exactly one match

1

New Number: 8.57 |  AESZ:  |  Superseeker: -36/5 -380  |  Hash: c2a931d298755811a60b7f8e5dd3afbe  

Degree: 8

\(5^{2} \theta^4+2^{2} 5 x\left(92\theta^4+208\theta^3+169\theta^2+65\theta+10\right)+2^{6} x^{2}\left(94\theta^4+937\theta^3+1739\theta^2+1175\theta+285\right)-2^{6} x^{3}\left(678\theta^4+1596\theta^3-2277\theta^2-4335\theta-1645\right)-2^{8} x^{4}\left(28\theta^4+2852\theta^3+8234\theta^2+7096\theta+2017\right)+2^{10} x^{5}\left(368\theta^4+2576\theta^3+4015\theta^2+2323\theta+456\right)-2^{13} x^{6}\left(94\theta^4+390\theta^3+438\theta^2+180\theta+19\right)+2^{14} x^{7}\left(34\theta^4+92\theta^3+103\theta^2+57\theta+13\right)-2^{16} x^{8}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, -8, 172, -5696, 231916, ...
--> OEIS
Normalized instanton numbers (n0=1): -36/5, 132/5, -380, 112043/20, -560656/5, ... ; Common denominator:...

Discriminant

\(-(4z+1)(64z^3-432z^2-76z-1)(5-16z+16z^2)^2\)

Local exponents

\(-\frac{ 1}{ 4}\) ≈\(-0.157556\) ≈\(-0.014327\)\(0\)\(\frac{ 1}{ 2}-\frac{ 1}{ 4}I\)\(\frac{ 1}{ 2}+\frac{ 1}{ 4}I\) ≈\(6.921883\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)
\(1\)\(1\)\(1\)\(0\)\(3\)\(3\)\(1\)\(1\)
\(2\)\(2\)\(2\)\(0\)\(4\)\(4\)\(2\)\(1\)

Note:

This is operator "8.57" from ...

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