Summary

You searched for: inst=1139

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New Number: 5.119 |  AESZ:  |  Superseeker: 138 278872  |  Hash: 61d7a82df3cf3c429b6286bc39ccb426  

Degree: 5

\(\theta^4-2 3 x\left(42\theta^4+204\theta^3+145\theta^2+43\theta+5\right)-2^{2} x^{2}\left(26932\theta^4+40768\theta^3-6943\theta^2-8482\theta-1635\right)-2^{4} 3^{2} 5 x^{3}\left(11156\theta^4+3848\theta^3+1777\theta^2+901\theta+180\right)-2^{7} 3^{3} 5^{2} x^{4}(2\theta+1)(304\theta^3+356\theta^2+97\theta-15)+2^{10} 3^{3} 5^{5} x^{5}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 30, 4530, 1074900, 312527250, ...
--> OEIS
Normalized instanton numbers (n0=1): 138, 1139, 278872, 21493934, 3832908140, ... ; Common denominator:...

Discriminant

\((4z-1)(500z-1)(12z+1)(1+120z)^2\)

Local exponents

\(-\frac{ 1}{ 12}\)\(-\frac{ 1}{ 120}\)\(0\)\(\frac{ 1}{ 500}\)\(\frac{ 1}{ 4}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(1\)\(3\)\(0\)\(1\)\(1\)\(1\)
\(2\)\(4\)\(0\)\(2\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.119" from ...

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