Summary

You searched for: inst=11/5

Your search produced exactly one match

1

New Number: 5.107 |  AESZ: 364  |  Superseeker: 11/5 71/5  |  Hash: c5b4bc60bc9d39ea420bd49fad182557  

Degree: 5

\(5^{2} \theta^4-5 x\left(553\theta^4+722\theta^3+611\theta^2+250\theta+40\right)+2^{6} x^{2}\left(1914\theta^4+4722\theta^3+5519\theta^2+3010\theta+610\right)-2^{12} x^{3}\left(685\theta^4+2400\theta^3+3466\theta^2+2220\theta+500\right)+2^{19} x^{4}(2\theta+1)(30\theta^3+105\theta^2+122\theta+46)-2^{25} x^{5}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 8, 120, 2240, 50680, ...
--> OEIS
Normalized instanton numbers (n0=1): 11/5, -8/5, 71/5, 738, 26841/5, ... ; Common denominator:...

Discriminant

\(-(32768z^3-2560z^2+85z-1)(-5+64z)^2\)

Local exponents

\(0\) ≈\(0.023029\) ≈\(0.027548-0.023797I\) ≈\(0.027548+0.023797I\)\(\frac{ 5}{ 64}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)
\(0\)\(1\)\(1\)\(1\)\(3\)\(1\)
\(0\)\(2\)\(2\)\(2\)\(4\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.107" from ...

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