Summary

You searched for: inst=-986355/4

Your search produced 2 matches

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1

New Number: 6.35 |  AESZ:  |  Superseeker:  |  Hash: de26083962cade55a4938b4011d0008e  

Degree: 6

\(\theta^4-3 x\left(63\theta^4+234\theta^3+247\theta^2+130\theta+28\right)+2 3^{4} x^{2}\left(9\theta^4+522\theta^3+1207\theta^2+1058\theta+356\right)+2^{2} 3^{7} x^{3}\left(135\theta^4+270\theta^3-730\theta^2-1395\theta-696\right)-2^{3} 3^{10} x^{4}\left(63\theta^4+774\theta^3+1372\theta^2+817\theta+88\right)-2^{4} 3^{13} x^{5}\left(72\theta^4+72\theta^3-325\theta^2-629\theta-308\right)+2^{5} 3^{16} x^{6}(3\theta+5)(3\theta+4)(2\theta+3)^2\)

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Coefficients of the holomorphic solution: 1, 84, 7452, 692688, 66448116, ...
--> OEIS
Normalized instanton numbers (n0=1): 21, -1617/4, 7941, -986355/4, 8179455, ... ; Common denominator:...

Discriminant

\((54z-1)(27z-1)(54z+1)^2(108z-1)^2\)

Local exponents

\(-\frac{ 1}{ 54}\)\(0\)\(\frac{ 1}{ 108}\)\(\frac{ 1}{ 54}\)\(\frac{ 1}{ 27}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 4}{ 3}\)
\(1\)\(0\)\(-\frac{ 1}{ 2}\)\(1\)\(1\)\(\frac{ 3}{ 2}\)
\(3\)\(0\)\(1\)\(1\)\(1\)\(\frac{ 3}{ 2}\)
\(4\)\(0\)\(\frac{ 3}{ 2}\)\(2\)\(2\)\(\frac{ 5}{ 3}\)

Note:

This is operator "6.35" from ...

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2

New Number: 7.12 |  AESZ:  |  Superseeker: -21 -7941  |  Hash: 0841b278bc566a089b643bbe2460fe8b  

Degree: 7

\(\theta^4+3 x\left(99\theta^4+162\theta^3+139\theta^2+58\theta+10\right)+2 3^{4} x^{2}\left(135\theta^4+738\theta^3+945\theta^2+518\theta+116\right)-2^{2} 3^{7} x^{3}\left(117\theta^4-738\theta^3-2010\theta^2-1493\theta-406\right)-2^{3} 3^{10} x^{4}\left(333\theta^4+774\theta^3-898\theta^2-1269\theta-454\right)-2^{4} 3^{13} x^{5}\left(54\theta^4+1224\theta^3+1179\theta^2+347\theta-22\right)+2^{5} 3^{16} x^{6}\left(180\theta^4+72\theta^3-327\theta^2-359\theta-106\right)+2^{7} 3^{19} x^{7}(\theta+1)^2(6\theta+5)(6\theta+7)\)

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Coefficients of the holomorphic solution: 1, -30, 1458, -89076, 6250050, ...
--> OEIS
Normalized instanton numbers (n0=1): -21, -399, -7941, -986355/4, -8179455, ... ; Common denominator:...

Discriminant

\((27z+1)(54z+1)(54z-1)^2(108z+1)^3\)

Local exponents

\(-\frac{ 1}{ 27}\)\(-\frac{ 1}{ 54}\)\(-\frac{ 1}{ 108}\)\(0\)\(\frac{ 1}{ 54}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 5}{ 6}\)
\(1\)\(1\)\(\frac{ 1}{ 2}\)\(0\)\(1\)\(1\)
\(1\)\(1\)\(\frac{ 3}{ 2}\)\(0\)\(3\)\(1\)
\(2\)\(2\)\(2\)\(0\)\(4\)\(\frac{ 7}{ 6}\)

Note:

This is operator "7.12" from ...

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