Summary

You searched for: inst=-723497/68

Your search produced exactly one match

1

New Number: 5.106 |  AESZ: 360  |  Superseeker: 3169/17 16293835/17  |  Hash: 502b9ea354d34405e6925ab32d7f1cd2  

Degree: 5

\(17^{2} \theta^4+17 x\left(10622\theta^4-19904\theta^3-13913\theta^2-3961\theta-510\right)+3^{2} x^{2}\left(1596891\theta^4-10821444\theta^3+10580847\theta^2+6358884\theta+1355036\right)-3^{5} x^{3}\left(5472387\theta^4-81131922\theta^3-52565469\theta^2-9898488\theta+1434596\right)+2^{2} 3^{8} 127 x^{4}\left(318018\theta^4+157911\theta^3-445563\theta^2-476706\theta-130792\right)-2^{2} 3^{12} 5 127^{2} x^{5}(5\theta+3)(5\theta+4)(5\theta+6)(5\theta+7)\)

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Coefficients of the holomorphic solution: 1, 30, 414, -73680, -4205250, ...
--> OEIS
Normalized instanton numbers (n0=1): 3169/17, -723497/68, 16293835/17, -1870341966/17, 251152956621/17, ... ; Common denominator:...

Discriminant

\(-(2278125z^3-33831z^2+182z-1)(17+6858z)^2\)

Local exponents

\(-\frac{ 17}{ 6858}\)\(0\) ≈\(0.001817-0.005986I\) ≈\(0.001817+0.005986I\) ≈\(0.011217\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 3}{ 5}\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(\frac{ 4}{ 5}\)
\(3\)\(0\)\(1\)\(1\)\(1\)\(\frac{ 6}{ 5}\)
\(4\)\(0\)\(2\)\(2\)\(2\)\(\frac{ 7}{ 5}\)

Note:

This is operator "5.106" from ...

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