Summary

You searched for: inst=-641

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New Number: 8.29 |  AESZ: 304  |  Superseeker: -5 -641  |  Hash: cf055a245b1537ed4f2609fa56cf67aa  

Degree: 8

\(\theta^4+x\left(82\theta^4+98\theta^3+77\theta^2+28\theta+4\right)-x^{2}\left(636+2916\theta+4463\theta^2+1850\theta^3-553\theta^4\right)-2^{2} x^{3}\left(6087\theta^4+22542\theta^3+27199\theta^2+14916\theta+3136\right)-2^{5} x^{4}\left(7241\theta^4+22750\theta^3+42326\theta^2+29943\theta+7272\right)+2^{7} x^{5}\left(7524\theta^4+1998\theta^3-23019\theta^2-24627\theta-7186\right)+2^{8} x^{6}\left(22961\theta^4+93930\theta^3+88283\theta^2+28194\theta+1624\right)-2^{10} 13 x^{7}\left(1505\theta^4+3274\theta^3+2919\theta^2+1282\theta+236\right)+2^{14} 13^{2} x^{8}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, -4, 112, -3712, 155536, ...
--> OEIS
Normalized instanton numbers (n0=1): -5, 469/8, -641, 50173/4, -276231, ... ; Common denominator:...

Discriminant

\((16z-1)(64z^3-432z^2-76z-1)(-1-11z+52z^2)^2\)

Local exponents

≈\(-0.157556\)\(\frac{ 11}{ 104}-\frac{ 1}{ 104}\sqrt{ 329}\) ≈\(-0.014327\)\(0\)\(\frac{ 1}{ 16}\)\(\frac{ 11}{ 104}+\frac{ 1}{ 104}\sqrt{ 329}\) ≈\(6.921883\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)
\(1\)\(3\)\(1\)\(0\)\(1\)\(3\)\(1\)\(1\)
\(2\)\(4\)\(2\)\(0\)\(2\)\(4\)\(2\)\(1\)

Note:

This operator has a second MUM-point at infinity corresponding to operator 8.28

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