Summary

You searched for: inst=-229968

Your search produced exactly one match

1

New Number: 5.38 |  AESZ: 223  |  Superseeker: 18 64744/3  |  Hash: e3ab25cffe4a0968b175bd9e98c96427  

Degree: 5

\(\theta^4+2 3 x\theta(48\theta^3-12\theta^2-7\theta-1)+2^{2} 3^{3} x^{2}\left(392\theta^4+488\theta^3+775\theta^2+376\theta+64\right)+2^{4} 3^{5} x^{3}\left(1184\theta^4+3288\theta^3+3512\theta^2+1635\theta+278\right)+2^{6} 3^{8} x^{4}(169\theta^2+361\theta+238)(2\theta+1)^2+2^{11} 3^{11} x^{5}(2\theta+1)^2(2\theta+3)^2\)

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Coefficients of the holomorphic solution: 1, 0, -432, 7200, 1587600, ...
--> OEIS
Normalized instanton numbers (n0=1): 18, -873, 64744/3, -229968, -1628892, ... ; Common denominator:...

Discriminant

\((36z+1)(13824z^2+36z+1)(1+108z)^2\)

Local exponents

\(-\frac{ 1}{ 36}\)\(-\frac{ 1}{ 108}\)\(-\frac{ 1}{ 768}-\frac{ 5}{ 2304}\sqrt{ 15}I\)\(-\frac{ 1}{ 768}+\frac{ 5}{ 2304}\sqrt{ 15}I\)\(0\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(1\)\(1\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(3\)\(1\)\(1\)\(0\)\(\frac{ 3}{ 2}\)
\(2\)\(4\)\(2\)\(2\)\(0\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.38" from ...

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