Summary

You searched for: inst=-188832

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1

New Number: 4.55 |  AESZ: 276  |  Superseeker: -188832 -101990911789344  |  Hash: 797e27181bf0a060708a3d221ec79699  

Degree: 4

\(\theta^4-2^{4} 3 x\left(18432\theta^4-4608\theta^3-1024\theta^2+1280\theta+221\right)+2^{17} 3^{4} x^{2}\left(25344\theta^4-2304\theta^3+11680\theta^2+1472\theta-33\right)-2^{28} 3^{8} x^{3}\left(18432\theta^4+13824\theta^3+11392\theta^2+3264\theta+359\right)+2^{46} 3^{12} x^{4}(3\theta+1)(2\theta+1)^2(3\theta+2)\)

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Coefficients of the holomorphic solution: 1, 10608, 477012240, 30101658720000, 2213759644568010000, ...
--> OEIS
Normalized instanton numbers (n0=1): -188832, -3134817768, -101990911789344, -4414817659429205136, -223930278487379610386400, ... ; Common denominator:...

Discriminant

\((331776z-1)^2(110592z-1)^2\)

Local exponents

\(0\)\(\frac{ 1}{ 331776}\)\(\frac{ 1}{ 110592}\)\(\infty\)
\(0\)\(0\)\(0\)\(\frac{ 1}{ 3}\)
\(0\)\(1\)\(\frac{ 1}{ 2}\)\(\frac{ 1}{ 2}\)
\(0\)\(3\)\(\frac{ 1}{ 2}\)\(\frac{ 1}{ 2}\)
\(0\)\(4\)\(1\)\(\frac{ 2}{ 3}\)

Note:

Sporadic Operator.

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