Summary

You searched for: inst=-139

Your search produced exactly one match

1

New Number: 4.72 |  AESZ: 361  |  Superseeker: 20 -119332/9  |  Hash: f55eaa640956f064f5230c04d8173d60  

Degree: 4

\(\theta^4-2^{2} x\left(80\theta^4+88\theta^3+67\theta^2+23\theta+3\right)+2^{4} 3 x^{2}\left(928\theta^4+2080\theta^3+2176\theta^2+972\theta+153\right)-2^{10} 3^{2} x^{3}\left(272\theta^4+648\theta^3+511\theta^2+162\theta+18\right)+2^{12} 3^{6} x^{4}\left((2\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 12, 324, -6000, -2778300, ...
--> OEIS
Normalized instanton numbers (n0=1): 20, -139, -119332/9, -462222, -2113440, ... ; Common denominator:...

Discriminant

\((20736z^2-224z+1)(-1+48z)^2\)

Local exponents

\(0\)\(s_1\)\(s_2\)\(\frac{ 7}{ 1296}-\frac{ 1}{ 324}\sqrt{ 2}I\)\(\frac{ 7}{ 1296}+\frac{ 1}{ 324}\sqrt{ 2}I\)\(\frac{ 1}{ 48}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(1\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(1\)\(1\)\(1\)\(3\)\(\frac{ 1}{ 2}\)
\(0\)\(2\)\(2\)\(2\)\(2\)\(4\)\(\frac{ 1}{ 2}\)

Note:

Sporadic Operator. There is a second MUM-point hiding at infinity, corresponding to Operator AESZ 362/4.73

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