Summary

You searched for: inst=-122168/5

Your search produced exactly one match

1

New Number: 5.52 |  AESZ: 252  |  Superseeker: -232/5 -122168/5  |  Hash: cae57e93a6afb98313f62899d1f75e2e  

Degree: 5

\(5^{2} \theta^4-2^{2} 5 x\left(36\theta^4-636\theta^3-488\theta^2-170\theta-25\right)-2^{4} x^{2}\left(21301\theta^4+27148\theta^3-86889\theta^2-63110\theta-14975\right)+2^{8} 5 x^{3}\left(3907\theta^4-58863\theta^3-25285\theta^2+10878\theta+7151\right)+2^{10} 59 x^{4}\left(10981\theta^4-29878\theta^3-89811\theta^2-70372\theta-17759\right)+2^{15} 3 59^{2} x^{5}(4\theta+5)(3\theta+2)(3\theta+4)(4\theta+3)\)

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Coefficients of the holomorphic solution: 1, -20, 684, -32240, 1969900, ...
--> OEIS
Normalized instanton numbers (n0=1): -232/5, -7499/10, -122168/5, -4503443/5, -200467616/5, ... ; Common denominator:...

Discriminant

\((108z+1)(2048z^2+52z+1)(-5+472z)^2\)

Local exponents

\(-\frac{ 13}{ 1024}-\frac{ 7}{ 1024}\sqrt{ 7}I\)\(-\frac{ 13}{ 1024}+\frac{ 7}{ 1024}\sqrt{ 7}I\)\(-\frac{ 1}{ 108}\)\(0\)\(\frac{ 5}{ 472}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 2}{ 3}\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(\frac{ 3}{ 4}\)
\(1\)\(1\)\(1\)\(0\)\(3\)\(\frac{ 5}{ 4}\)
\(2\)\(2\)\(2\)\(0\)\(4\)\(\frac{ 4}{ 3}\)

Note:

This is operator "5.52" from ...

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