Summary

You searched for: h3=21

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1

New Number: 5.22 |  AESZ: 193  |  Superseeker: 129/7 41441/7  |  Hash: 44e6fc2823d5ff31e66059ba6b37f2ae  

Degree: 5

\(7^{2} \theta^4-7 x\left(1135\theta^4+2204\theta^3+1683\theta^2+581\theta+77\right)+x^{2}\left(28723\theta^4+40708\theta^3+13260\theta^2-1337\theta-896\right)-x^{3}\left(32126\theta^4+38514\theta^3+26511\theta^2+10731\theta+1806\right)+7 11 x^{4}\left(130\theta^4+254\theta^3+192\theta^2+65\theta+8\right)+11^{2} x^{5}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 11, 559, 42923, 3996751, ...
--> OEIS
Normalized instanton numbers (n0=1): 129/7, 1557/7, 41441/7, 1594332/7, 75470601/7, ... ; Common denominator:...

Discriminant

\((z^3+84z^2-159z+1)(-7+11z)^2\)

Local exponents

≈\(-85.852157\)\(0\) ≈\(0.00631\)\(\frac{ 7}{ 11}\) ≈\(1.845846\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)
\(1\)\(0\)\(1\)\(3\)\(1\)\(1\)
\(2\)\(0\)\(2\)\(4\)\(2\)\(1\)

Note:

There is a second MUM-point at infinity,
corresponding to Operator AESZ 198/5.25

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2

New Number: 5.35 |  AESZ: 218  |  Superseeker: 138/7 42984/7  |  Hash: a76111af659715caf2c4344eedd9d678  

Degree: 5

\(7^{2} \theta^4-2 3 7 x\left(192\theta^4+396\theta^3+303\theta^2+105\theta+14\right)+2^{2} 3 x^{2}\left(1188\theta^4+11736\theta^3+20431\theta^2+12152\theta+2436\right)+2^{2} 3^{3} x^{3}\left(532\theta^4+504\theta^3-3455\theta^2-3829\theta-1036\right)-2^{4} 3^{4} x^{4}(2\theta+1)(36\theta^3+306\theta^2+421\theta+156)-2^{6} 3^{4} x^{5}(2\theta+1)(3\theta+2)(3\theta+4)(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 12, 612, 48000, 4580100, ...
--> OEIS
Normalized instanton numbers (n0=1): 138/7, 1506/7, 42984/7, 235596, 78950334/7, ... ; Common denominator:...

Discriminant

\(-(1296z^3-864z^2+168z-1)(7+12z)^2\)

Local exponents

\(-\frac{ 7}{ 12}\)\(0\) ≈\(0.006145\) ≈\(0.330261-0.128447I\) ≈\(0.330261+0.128447I\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(\frac{ 2}{ 3}\)
\(3\)\(0\)\(1\)\(1\)\(1\)\(\frac{ 4}{ 3}\)
\(4\)\(0\)\(2\)\(2\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.35" from ...

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3

New Number: 5.70 |  AESZ: 287  |  Superseeker: 361/21 120472/21  |  Hash: 97932196c46a8712f6dcb11165d698be  

Degree: 5

\(3^{2} 7^{2} \theta^4-3 7 x\left(3289\theta^4+6098\theta^3+4645\theta^2+1596\theta+210\right)+2^{2} 5 x^{2}\left(7712\theta^4-46168\theta^3-106885\theta^2-67410\theta-13629\right)+2^{4} x^{3}\left(106636\theta^4+493416\theta^3+420211\theta^2+116361\theta+6090\right)-2^{8} 5 x^{4}(2\theta+1)(1916\theta^3+2622\theta^2+1077\theta+91)-2^{12} 5^{2} x^{5}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 10, 510, 38260, 3473470, ...
--> OEIS
Normalized instanton numbers (n0=1): 361/21, 4780/21, 120472/21, 1537864/7, 216261320/21, ... ; Common denominator:...

Discriminant

\(-(64z^3+800z^2+149z-1)(-21+80z)^2\)

Local exponents

≈\(-12.310784\) ≈\(-0.195701\)\(0\) ≈\(0.006485\)\(\frac{ 21}{ 80}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(1\)\(1\)\(0\)\(1\)\(3\)\(1\)
\(2\)\(2\)\(0\)\(2\)\(4\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.70" from ...

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