Summary

You searched for: dim_h=17

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1

New Number: 5.10 |  AESZ: 59  |  Superseeker: 30/7 124  |  Hash: f47563daeb0f7328bd675f13cfb84a55  

Degree: 5

\(7^{2} \theta^4-2 7 x\left(257\theta^4+520\theta^3+435\theta^2+175\theta+28\right)+2^{2} x^{2}\left(13497\theta^4+55536\theta^3+81222\theta^2+50337\theta+11396\right)-2^{3} x^{3}\left(17201\theta^4+114996\theta^3+248466\theta^2+202629\theta+55412\right)-2^{4} x^{4}\left(5762\theta^4+29668\theta^3+48150\theta^2+31741\theta+7412\right)-2^{5} 3 x^{5}(4\theta+5)(3\theta+2)(3\theta+4)(4\theta+3)\)

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Coefficients of the holomorphic solution: 1, 8, 144, 3680, 114400, ...
--> OEIS
Normalized instanton numbers (n0=1): 30/7, 129/14, 124, 72129/56, 130434/7, ... ; Common denominator:...

Discriminant

\(-(4z-1)(16z-1)(54z-1)(7+2z)^2\)

Local exponents

\(-\frac{ 7}{ 2}\)\(0\)\(\frac{ 1}{ 54}\)\(\frac{ 1}{ 16}\)\(\frac{ 1}{ 4}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 2}{ 3}\)
\(1\)\(0\)\(1\)\(1\)\(1\)\(\frac{ 3}{ 4}\)
\(3\)\(0\)\(1\)\(1\)\(1\)\(\frac{ 5}{ 4}\)
\(4\)\(0\)\(2\)\(2\)\(2\)\(\frac{ 4}{ 3}\)

Note:

This is operator "5.10" from ...

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2

New Number: 5.20 |  AESZ: 186  |  Superseeker: 49/19 1761/19  |  Hash: b3d164f22d02de1efcd62d3aa9ab5ce4  

Degree: 5

\(19^{2} \theta^4-19 x\left(700\theta^4+1238\theta^3+999\theta^2+380\theta+57\right)-x^{2}\left(64745\theta^4+368006\theta^3+609133\theta^2+412756\theta+102258\right)+3^{3} x^{3}\left(6397\theta^4+12198\theta^3-11923\theta^2-27360\theta-11286\right)+3^{6} x^{4}\left(64\theta^4+1154\theta^3+2425\theta^2+1848\theta+486\right)-3^{11} x^{5}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 3, 51, 1029, 25299, ...
--> OEIS
Normalized instanton numbers (n0=1): 49/19, 252/19, 1761/19, 18990/19, 246159/19, ... ; Common denominator:...

Discriminant

\(-(z+1)(243z^2+35z-1)(-19+27z)^2\)

Local exponents

\(-1\)\(-\frac{ 35}{ 486}-\frac{ 13}{ 486}\sqrt{ 13}\)\(0\)\(-\frac{ 35}{ 486}+\frac{ 13}{ 486}\sqrt{ 13}\)\(\frac{ 19}{ 27}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(1\)\(1\)\(0\)\(1\)\(3\)\(1\)
\(2\)\(2\)\(0\)\(2\)\(4\)\(1\)

Note:

There is a second MUM-point at infinity, corresponding to Operator AESZ 187/5.21

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3

New Number: 5.80 |  AESZ: 311  |  Superseeker: 25/13 875/13  |  Hash: 8219f3f4bd56f6c2b2cc3ab9093b65d1  

Degree: 5

\(13^{2} \theta^4-13 x\left(327\theta^4+1038\theta^3+857\theta^2+338\theta+52\right)-2^{4} x^{2}\left(12848\theta^4+42008\theta^3+52082\theta^2+28548\theta+5707\right)-2^{11} x^{3}\left(122\theta^4-1872\theta^3-6341\theta^2-5772\theta-1547\right)+2^{16} x^{4}(2\theta+1)(76\theta^3+426\theta^2+570\theta+227)+2^{23} x^{5}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 4, 84, 1840, 56980, ...
--> OEIS
Normalized instanton numbers (n0=1): 25/13, 1359/52, 875/13, 36572/13, 256800/13, ... ; Common denominator:...

Discriminant

\((8192z^3-896z^2-35z+1)(13+64z)^2\)

Local exponents

\(-\frac{ 13}{ 64}\) ≈\(-0.045147\)\(0\) ≈\(0.020117\) ≈\(0.134405\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(3\)\(1\)\(0\)\(1\)\(1\)\(1\)
\(4\)\(2\)\(0\)\(2\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.80" from ...

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4

New Number: 8.9 |  AESZ: 174  |  Superseeker: 16 -13  |  Hash: 3f987b46d9ebf201eeead1a885b78e66  

Degree: 8

\(\theta^4-x(11\theta^2+11\theta+3)(17\theta^2+17\theta+6)+x^{2}\left(8711\theta^4+33980\theta^3+47095\theta^2+26230\theta+5232\right)-2^{3} 3^{2} x^{3}\left(187\theta^4-1122\theta^3-3436\theta^2-2595\theta-684\right)+2^{4} 3^{2} x^{4}\left(8639\theta^4+17278\theta^3-11650\theta^2-20289\theta-6102\right)+2^{6} 3^{4} x^{5}\left(187\theta^4+1870\theta^3+1052\theta^2-163\theta-216\right)+2^{6} 3^{4} x^{6}\left(8711\theta^4+864\theta^3-2579\theta^2+864\theta+828\right)+2^{9} 3^{6} x^{7}(11\theta^2+11\theta+3)(17\theta^2+17\theta+6)+2^{12} 3^{8} x^{8}\left((\theta+1)^4\right)\)

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Coefficients of the holomorphic solution: 1, 18, 798, 45864, 2994894, ...
--> OEIS
Normalized instanton numbers (n0=1): 16, 7/2, -13, 11663/2, -26414, ... ; Common denominator:...

Discriminant

\((81z^2+99z-1)(64z^2+88z-1)(1+72z^2)^2\)

Local exponents

\(-\frac{ 11}{ 16}-\frac{ 5}{ 16}\sqrt{ 5}\)\(-\frac{ 11}{ 18}-\frac{ 5}{ 18}\sqrt{ 5}\)\(0-\frac{ 1}{ 12}\sqrt{ 2}I\)\(0\)\(0+\frac{ 1}{ 12}\sqrt{ 2}I\)\(-\frac{ 11}{ 18}+\frac{ 5}{ 18}\sqrt{ 5}\)\(-\frac{ 11}{ 16}+\frac{ 5}{ 16}\sqrt{ 5}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(0\)\(1\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(1\)\(1\)\(1\)
\(1\)\(1\)\(3\)\(0\)\(3\)\(1\)\(1\)\(1\)
\(2\)\(2\)\(4\)\(0\)\(4\)\(2\)\(2\)\(1\)

Note:

Hadamard product $ b \ast g$. This operator has a second MUM-point at infinity with the same instanton numbers. It
can be reduced to an operator of degree 4 with a single MUM-point defined over $Q(\sqrt{?})$.

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