Summary

You searched for: c3=-116

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1

New Number: 2.53 |  AESZ: 29  |  Superseeker: 14 10424/3  |  Hash: 92e8a038051b3fb8e0cc6ad6a52b8bfb  

Degree: 2

\(\theta^4-2 x(2\theta+1)^2(17\theta^2+17\theta+5)+2^{2} x^{2}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 10, 438, 28900, 2310070, ...
--> OEIS
Normalized instanton numbers (n0=1): 14, 303/2, 10424/3, 113664, 4579068, ... ; Common denominator:...

Discriminant

\(1-136z+16z^2\)

Local exponents

\(0\)\(\frac{ 17}{ 4}-3\sqrt{ 2}\)\(\frac{ 17}{ 4}+3\sqrt{ 2}\)\(\infty\)
\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(1\)\(1\)
\(0\)\(1\)\(1\)\(1\)
\(0\)\(2\)\(2\)\(\frac{ 3}{ 2}\)

Note:

Hadamard product $I \ast \gamma$

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2

New Number: 2.55 |  AESZ: 42  |  Superseeker: 8 1000  |  Hash: c389d3bc0e31801bc4b7b3e186702bc9  

Degree: 2

\(\theta^4-2^{3} x(2\theta+1)^2(3\theta^2+3\theta+1)+2^{6} x^{2}(2\theta+1)(\theta+1)^2(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 8, 240, 10880, 597520, ...
--> OEIS
Normalized instanton numbers (n0=1): 8, 63, 1000, 44369/2, 606168, ... ; Common denominator:...

Discriminant

\(1-96z+256z^2\)

Local exponents

\(0\)\(\frac{ 3}{ 16}-\frac{ 1}{ 8}\sqrt{ 2}\)\(\frac{ 3}{ 16}+\frac{ 1}{ 8}\sqrt{ 2}\)\(\infty\)
\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(1\)\(1\)
\(0\)\(1\)\(1\)\(1\)
\(0\)\(2\)\(2\)\(\frac{ 3}{ 2}\)

Note:

Hadamard product $I \ast \epsilon$

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3

New Number: 2.61 |  AESZ: 26  |  Superseeker: 10 1724  |  Hash: f3fc09474973b19b8bdb783e3322eb65  

Degree: 2

\(\theta^4-2 x(2\theta+1)^2(13\theta^2+13\theta+4)-2^{2} 3 x^{2}(2\theta+1)(3\theta+2)(3\theta+4)(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 8, 288, 15200, 968800, ...
--> OEIS
Normalized instanton numbers (n0=1): 10, 191/2, 1724, 45680, 1478214, ... ; Common denominator:...

Discriminant

\(-(4z+1)(108z-1)\)

Local exponents

\(-\frac{ 1}{ 4}\)\(0\)\(\frac{ 1}{ 108}\)\(\infty\)
\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(0\)\(1\)\(\frac{ 2}{ 3}\)
\(1\)\(0\)\(1\)\(\frac{ 4}{ 3}\)
\(2\)\(0\)\(2\)\(\frac{ 3}{ 2}\)

Note:

A-incarnation: $X(1,1,1,1,2) \subset Grass(2,6)$

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4

New Number: 5.113 |  AESZ: 403  |  Superseeker: -29/5 -1481/5  |  Hash: 492c8a69e87d470c87b9557834f0fc5b  

Degree: 5

\(5^{2} \theta^4+5 x\left(487\theta^4+878\theta^3+709\theta^2+270\theta+40\right)+2^{5} x^{2}\left(1013\theta^4+2639\theta^3+2943\theta^2+1520\theta+280\right)-2^{8} x^{3}\left(2169\theta^4+14880\theta^3+30789\theta^2+22440\theta+5240\right)-2^{12} x^{4}(2\theta+1)(518\theta^3+2397\theta^2+2940\theta+1048)-2^{16} 3 x^{5}(2\theta+1)(3\theta+2)(3\theta+4)(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, -8, 216, -8000, 359800, ...
--> OEIS
Normalized instanton numbers (n0=1): -29/5, 229/5, -1481/5, 43173/5, -155267, ... ; Common denominator:...

Discriminant

\(-(27z+1)(1024z^2-64z-1)(5+16z)^2\)

Local exponents

\(-\frac{ 5}{ 16}\)\(-\frac{ 1}{ 27}\)\(\frac{ 1}{ 32}-\frac{ 1}{ 32}\sqrt{ 2}\)\(0\)\(\frac{ 1}{ 32}+\frac{ 1}{ 32}\sqrt{ 2}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(1\)\(1\)\(1\)\(0\)\(1\)\(\frac{ 2}{ 3}\)
\(3\)\(1\)\(1\)\(0\)\(1\)\(\frac{ 4}{ 3}\)
\(4\)\(2\)\(2\)\(0\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.113" from ...

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