Summary

You searched for: c2h=-16

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1

New Number: 5.13 |  AESZ: 83  |  Superseeker: -80 -174096  |  Hash: 171e1251d8e4f7de878d0d07de6f58ab  

Degree: 5

\(\theta^4-2^{4} x\left(88\theta^4+32\theta^3+33\theta^2+17\theta+3\right)+2^{9} x^{2}\left(1504\theta^4+1408\theta^3+1436\theta^2+596\theta+93\right)-2^{18} x^{3}\left(776\theta^4+1344\theta^3+1381\theta^2+651\theta+117\right)+2^{23} 3 x^{4}(2\theta+1)(512\theta^3+1152\theta^2+1054\theta+339)-2^{31} 3^{2} x^{5}(2\theta+1)(4\theta+3)(4\theta+5)(2\theta+3)\)

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Coefficients of the holomorphic solution: 1, 48, 5328, 779520, 131619600, ...
--> OEIS
Normalized instanton numbers (n0=1): -80, -2954, -174096, -13270953, -1179175536, ... ; Common denominator:...

Discriminant

\(-(128z-1)(384z-1)^2(256z-1)^2\)

Local exponents

\(0\)\(\frac{ 1}{ 384}\)\(\frac{ 1}{ 256}\)\(\frac{ 1}{ 128}\)\(\infty\)
\(0\)\(0\)\(0\)\(0\)\(\frac{ 1}{ 2}\)
\(0\)\(1\)\(\frac{ 1}{ 2}\)\(1\)\(\frac{ 3}{ 4}\)
\(0\)\(3\)\(\frac{ 1}{ 2}\)\(1\)\(\frac{ 5}{ 4}\)
\(0\)\(4\)\(1\)\(2\)\(\frac{ 3}{ 2}\)

Note:

This is operator "5.13" from ...

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